llations in a 1)
TABULATE:
i:1,2,3,4,5,
L(cm):80.00,70.00,60.00,50.00,40.00
t1(s):17.87,16.22,16.09,14.08,13.28
t2(2):17.56,16.46,15.09,14.77,13.36
t(s)mean:17.715,16.340,15.590,14.425,13.320
T(t/10)s:1.7715,1.6340,1.5590,1.4425,1.3320
LogT(s):0.2483,0.2133,0.1928,0.1591,0.1212
Log L(cm):1.9031,1.8451,1.7782,1.6990,1.6021
Log T*10^-2(s):24.83,21.33,19.28,15.91,12.12
Log L*10^-1(cm):19.031,18.451,17.782,16.990,16.021
SLOPE(s)=(LogT2*10^-2 - LogT1*10^-2)(/Log L2 *10^-1 - LogL1*10^-1)
=(21.33-12.12(s))*10^-2/(18.50-16.02(cm)*10^-1)
=3.714*10^-1
=0.3714cm^-1
2b)
bi)The boiling point of a liquid is the temperature
at which the vapor pressure of the
liquid equals the pressure surrounding the liquid
and the
liquid changes into a vapor.
bii) impurities increases the temperature range a
substance can exist as a liquid
No3
*Precaution for electricity*
i)I avoid parallax error when reading ammeter and voltmeter.
ii)I ensure tight connection
iii)I open the key when reading and not taken to ensure that cells do not run down
iv)I ensure that the jockey is not dragged alone the potentiometer wire
*Precaution for oscillation*
i)I ensure that the support of the bifilar pendulum is rigid
ii)I ensure smooth and regular oscillations in a horizontal plane.
iii)I avoid error due to parallax in reading the meter rule and stop watch.
iv)I avoided zero error in the reading of the stopwatch.
1axi)
i)ensured supports of pendula were rigged
ii)avoided parallax error on meter rule/stop watch
1bi)
simple harmonic motion is the motion of a body whose acceleration is always direct towards a fixed point and is proportional to the displacement from the fixed points
1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with corresponding Log L read L correctly determined
=================================
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
3viii)
i)ensured clean/tight terminals
ii)open key when reading was taken
iii)avoided parallax error in ammeter/voltmeter
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
=====KEEP REFRESHING====
1axi)
i)ensured supports of pendula were rigged
ii)avoided parallax error on meter rule/stop watch
1bi)
simple harmonic motion is the motion of a body whose acceleration is always direct towards a fixed point and is proportional to the displacement from the fixed points
1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with corresponding Log L read L correctly determined
================
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
VERIFIED 2017 WAEC PRACTICAL PHYSICS ANSWER.
1a) Number of oscillation = 10
{NOTE: this sign ^ means Raise to power}
S/N | L(cm) | T(s) | T=t/10(s) | T^2(s)^2 |
L(cm)^3
1. | 90.00 | 4.70 | 0.470 | 0.2209 | 729000
2. | 85.00 | 4.50 | 0.450 | 0.2025 | 614125
3. | 80.00 | 4.30 | 0.430 | 0.1849 | 512000
4. | 75.00 | 4.00 | 0.400 | 0.1600 | 421875
5. | 70.00 | 3.80 | 0.380 | 0.1444 | 343000
(Ix) Slope(s),= 720,000 - 200,000/ 0.225 -
0.11
S= 520000/0.115
S= 4521739.13cm^3/s^2
(X) PRECAUTIONS
(I) I made sure rigid support of the
apparatus
(ii) I avoided error due to parallax when
reading my
stopwatch
(iii) I made sure I oscillate at small angle
(Iv) I minimized draught
(1bi) The mas M series as an oscillator
(1bii)
(I) Simple pendulum bob
(ii) Loaded test tube
(iii) Loaded spiral spring
(Iv) Skin of talking drum
(V) Helical spring
(3a)
E.M.F (E) = 3.00v , Io = 0.62A
S/N | PJ=L(cm) | I(A) | y=E/A(v/A) |
1. | 20.00 | 0.58 | 5.172 |
2. | 30.00 | 0.50 | 6.000 |
3. | 40.00 | 0.45 | 6.667 |
4. | 50.00 | 0.40 | 7.500 |
5. | 60.00 | 0.35 | 8.571 |
6. | 70.00 | 0.32 | 9.375 |
(Vii)
Slope(s)= Y2 - Y1 / L2 - L1
S = 10.20 - 4.00/ 80 - 7
S = 6.20/73
S= 0.0849v/A
The intercept C on the vertical axis = 2.70v/
A
(Viii)
K = Io C
K = 0.62 x 2.70
K = 1.674
(Ix)PRECAUTIONS
(I) I ensured hight connection of the wire
of all the instrument use
(ii) I maintained steady flow of current
before taking my reading
(iii) I made sure that I removed the key
after each reading to avoid drained of the
cell
(Iv) I avoided error due to parallax on
ammeter
(V) I made sure that the jockey is not
dragged on the wire of the potentiometer
(3bi)
The key K.
This is because the key serves a switch
which does not drawn any current or
voltage from the source of E.M.F
(3b)
From the defination of Resistivity
P = RA/ L
But A = pai D^2/ 4
P = R pai D^2/4L
P4L = pai R D^2
L = pai R D^2/ 4P
Where P is the resitivity of the material. plane.
iii)I avoid error due to parallax in reading the meter rule and stop watch.
iv)I avoided zero error in the reading of the stopwatch.
1axi)
i)ensured supports of pendula were rigged
ii)avoided parallax error on meter rule/stop watch
1bi)
simple harmonic motion is the motion of a body whose acceleration is always direct towards a fixed point and is proportional to the displacement from the fixed points
1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with corresponding Log L read L correctly determined
=================================
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
3viii)
i)ensured clean/tight terminals
ii)open key when reading was taken
iii)avoided parallax error in ammeter/voltmeter
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
=====KEEP REFRESHING====
1axi)
i)ensured supports of pendula were rigged
ii)avoided parallax error on meter rule/stop watch
1bi)
simple harmonic motion is the motion of a body whose acceleration is always direct towards a fixed point and is proportional to the displacement from the fixed points
1bii)
T=1.2secs
Log 1.2=0.079
0079 shown on graph with corresponding Log L read L correctly determined
================
3axi)
i)ensured clean/tight terminals
ii)open key when reading was taken
3bi)
i)brightness of the bulb increases
ii)voltage/current through the bulb increases
3bii)
i)diode
ii)transistor
VERIFIED 2017 WAEC PRACTICAL PHYSICS ANSWER.
1a) Number of oscillation = 10
{NOTE: this sign ^ means Raise to power}
S/N | L(cm) | T(s) | T=t/10(s) | T^2(s)^2 |
L(cm)^3
1. | 90.00 | 4.70 | 0.470 | 0.2209 | 729000
2. | 85.00 | 4.50 | 0.450 | 0.2025 | 614125
3. | 80.00 | 4.30 | 0.430 | 0.1849 | 512000
4. | 75.00 | 4.00 | 0.400 | 0.1600 | 421875
5. | 70.00 | 3.80 | 0.380 | 0.1444 | 343000
(Ix) Slope(s),= 720,000 - 200,000/ 0.225 -
0.11
S= 520000/0.115
S= 4521739.13cm^3/s^2
(X) PRECAUTIONS
(I) I made sure rigid support of the
apparatus
(ii) I avoided error due to parallax when
reading my
stopwatch
(iii) I made sure I oscillate at small angle
(Iv) I minimized draught
(1bi) The mas M series as an oscillator
(1bii)
(I) Simple pendulum bob
(ii) Loaded test tube
(iii) Loaded spiral spring
(Iv) Skin of talking drum
(V) Helical spring
(3a)
E.M.F (E) = 3.00v , Io = 0.62A
S/N | PJ=L(cm) | I(A) | y=E/A(v/A) |
1. | 20.00 | 0.58 | 5.172 |
2. | 30.00 | 0.50 | 6.000 |
3. | 40.00 | 0.45 | 6.667 |
4. | 50.00 | 0.40 | 7.500 |
5. | 60.00 | 0.35 | 8.571 |
6. | 70.00 | 0.32 | 9.375 |
(Vii)
Slope(s)= Y2 - Y1 / L2 - L1
S = 10.20 - 4.00/ 80 - 7
S = 6.20/73
S= 0.0849v/A
The intercept C on the vertical axis = 2.70v/
A
(Viii)
K = Io C
K = 0.62 x 2.70
K = 1.674
(Ix)PRECAUTIONS
(I) I ensured hight connection of the wire
of all the instrument use
(ii) I maintained steady flow of current
before taking my reading
(iii) I made sure that I removed the key
after each reading to avoid drained of the
cell
(Iv) I avoided error due to parallax on
ammeter
(V) I made sure that the jockey is not
dragged on the wire of the potentiometer
(3bi)
The key K.
This is because the key serves a switch
which does not drawn any current or
voltage from the source of E.M.F
(3b)
From the defination of Resistivity
P = RA/ L
But A = pai D^2/ 4
P = R pai D^2/4L
P4L = pai R D^2
L = pai R D^2/ 4P
Where P is the resitivity of the material. CRIBE Practical Physics RUNS
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